Question

calculate ∆U at 298K for the reaction,C2H4+HCl=C2H5Cl,∆H=-72.3Kj how much PV work is done?​

Answer 1

Explanation:

the formula is

∆H=∆U+∆nRT

∆n for up reaction is =(stoichiometric product-reactent)

os ∆n is -1

then put value in formula

-73.3=∆U-1×8.3×298/1000(to convert into kj)

so we get

-69.8266 kj is answer

Answer 2

Right answer.

yessssssss