calculate ∆U,q and w when 2.0 mol of an ideal gas at 25°C are compressed isothermally and reversibly from 1.0bar to 10.0bar?
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Answered by
3
Answer:
∆U = 0
q = -11411.69
w= 11411.69
Explanation:
n=2
P1 = 10
P2= 1
R = 8.314. ( constant value)
t = 25 + 273 K
= 298 K
w = 2.303nRt log P1/P2. ( using this formula)
w= 2.303×2×8.314×298×log 10/1
w= 11411.69×1. (log 10 = 1)
w = 11412. ( by round of)
∆U = 0. ( because temp is constant so ∆U =0)
∆U = q + w
0 = q + 11412
q = 0- 11412
q = -11412
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