Calculate unit cell volume and number of atoms per unit cell in tetragonal
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Atoms on a corner are shared by eight unit cells and hence contribute only \({1 \over 8}\) atom per unit cell, giving 8×18 =1 Au atom per unit cell. The total number of Au atoms in each unit cell is thus 3 + 1 = 4. Metallic iron has a body-centered cubic unit cell (part (b) in Figure 12.5).
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Atoms on a corner are shared by eight unit cells and hence contribute only \({1 \over 8}\) atom per unit cell, giving 8×18 =1 Au atom per unit cell.
The total number of Au atoms in each unit cell is thus 3 + 1 = 4. Metallic iron has a body-centered cubic unit cell
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