Question

Calculate vapour pressure of a solution containing 15.4g of cane sugar in 175g of water at 100^oc( require immediate answer)

Answer 1

Answer:

at 0°C, 179 g of sucrose dissolves in 100 g of H2O ... Also, collect the vapor and then ... Now, we can substitute moles, temperature, and pressure into the ideal gas

Answer 2

Answer:

ΔT

ΔT b

ΔT b

ΔT b =K

ΔT b =K b

ΔT b =K b

ΔT b =K b × molality

ΔT b =K b × molality0.80=0.52×

ΔT b =K b × molality0.80=0.52× M

ΔT b =K b × molality0.80=0.52× M w

ΔT b =K b × molality0.80=0.52× M w

ΔT b =K b × molality0.80=0.52× M w ×185

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w =

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.8

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000 M

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000 M w

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000 M w

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000 M w =43.92 g mol

ΔT b =K b × molality0.80=0.52× M w ×18512.5×1000 M w = 185×0.80.52×12.5×1000 M w =43.92 g mol −1

I hope it helps u ☺️❣❣✌️.......