Calculate vapour pressure of toluene at 100 0C if it is assumed that toluene obeys trouton’s rule
and the normal boiling point is 110.62 0C.
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Answer:
Let X
B
and X
T
be the mole fractions of benzene and toluene in solution.
XT=1−XB
P
total
=PB+PT
P
total
is the total pressure of the mixture. It is 1 atm or 760 torr.
P
B
is the partial pressure of benzene. P
T
is partial pressure of toluene.
P
B
=X
B
P
B
o
=X
B
(1375)
P
T
=X
T
P
T
o
=(1−X
B
)558
P
total
=760=(1375)X
B
+558(1−X
B
)
760=(817)X
B
+558
(817)X
B
=202
X
B
=0.2472
X
T
=1−X
B
=0.7528
Let Y
B
and Y
T
be the mole fractions of benzene and toluene in the vapour phase.
Y
B
=
P
total
P
B
=
760
1375×0.2472
=0.4473
Y
T
=1−0.4473=0.5527
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