Question

calculate velocity of balls after one dimensional collision ? ​

Answer 1

Answer:

Explanation:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as:

v2f=2⋅m1(m2+m1)v1i+(m2−m1)

(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

Answer 2

From the conservation of momentum, the formula during a collision is given by:

m1v1 + m2v2 = m1v'1 + m2v'2.

In the case of a completely inelastic collision, the final velocity of the system is determined with

v' = (m1v1 + m2v2)/m1 + m2

• The one-dimensional derivation is shown in the attached file.

• The mass body m₁ moves with the speed u₁ and the mass body m₂ moves with the speed u₂, after the impact the speed became v₁ and v₂.

• The result is v₂ v₁ = u₁ u₂.

• In a frontal elastic collision, in which the projectile is much more massive than the target, the velocity of the target particle after the collision will be about twice that of the projectile, and the velocity of the projectile remains essentially unchanged.m1 • delta v1 = m2 • delta v2

• This equation states that in a collision, one object gains momentum and the other object loses momentum.

• The amount of momentum gained by one object is equal to the amount of momentum lost by the other object. The total momentum possessed by the two objects does not change.

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