Question

Calculate vol of O2 at STP required
for
combustion of 1000g Sulphur
which has 4%
incombustible matter (S=32, 0=16)​

Answer 1

Answer:

CHECK IT OUT

Explanation:

Solution :

Mass of sulphur = 1000 g

Mass of combustible matter =1000×4100=40 g

Mass of combustible matter (pure sulphur) =1000−40=960 g

Step I. Volume of oxygen required

The equation for the combustion reaction is :

S32g+O222.4L→SO2

32g of sulphur require O2=22.4L

1 g of sulphur require O2=22.432L

960 g of sulphur require O2=22.432×960=672L

Step II. Volume of air required

If O2 is 21 L, then air =100L

If O2 is 1 L, then air =10021L

If O2 is 672 L, then air =10021×672L=3200L.