Question

Calculate volume (at STP) of dioxygen required to combust 2.8 g of CO

Answer 1

Answer:

Explanation:

CH41mol16g+2O22mol2×22.4L→CO2+2H2O

At STP, ∵ For the combustion of 16gCH4,

oxygen Required =2×22.4L

∴ For the combustion of 4gCH4,

oxygen required will be

=2×22.4×416L

=11.2L