Question

calculate volume of 0.1 molar acid required to react with hundred ml of 0.1 molar KMnO4 solution​

Answer 1

Answer:

Explanation:

2KMnO  

4

​

+5H  

2

​

C  

2

​

O  

4

​

.2H  

2

​

O+H  

2

​

SO  

4

​

⇌2MnSO  

4

​

+K  

2

​

SO  

4

​

+10CO  

2

​

+10H  

2

​

O

Two moles of KMnO  

4

​

 reacts with 5 moles of oxalic acid.

M  

1

​

V  

1

​

=M  

2

​

V  

2

​

 

2(0.1∗V  

1

​

)=5(0.1∗100)

0.2∗V  

1

​

=50=>x=250ml