Calculate volume of 0.1 N HCl needed for complete neutralization of 20 ml of 0.5 N NaOH.
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Answered by
1
Explanation:
Answer
Correct option is
A
40ml
n-factor of NaOH = 1
n-factor of HCl = 1
As we know, N
1
V
1
=N
2
V
2
(0.1×1)(.02)=(.05×1)×V
2
V
2
=0.04 litre
V
2
=40ml
Answered by
1
Answer:Correct option is
A
40ml
n-factor of NaOH = 1
n-factor of HCl = 1
As we know, N
1
V
1
=N
2
V
2
(0.1×1)(.02)=(.05×1)×V
2
V
2
=0.04 litre
V
2
=40ml
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