Question

Calculate volume of 0.4 M NaOH required to react with following mixture HCl (1 mol) + H2SO4 (2 mol).​

Answer 1

Answer:

12.5 Lit

Explanation:

KHC

2

O

4

and H

2

C

2

O

4

contain one and 2 acidic hydrogens respectively. SO the mixture of 1 mole KHC

2

O

4

and 2 moles of H

2

C

2

O

4

contains total of 5 mols of acidic hydrogens.

now, 1000ml 0.4M NaOH=0.4 mole of NaOH

Required volume of 0.4M NaOH=

0.4

5

×1000ml

=12.5×10

3

ml=12.5lit .

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