Question

calculate volume of 56 L of oxygen gas ​

Answer 1

Explanation:

1 g = 1 / 217 = 4.608 × 10-3 mole. The number of moles of oxygen is half the number of moles of mercury oxide = 2.304 × 10-3. If the volume of one mole of gas is about 24,000 cm3, then the volume of oxygen obtained will be 2.304 × 10-3 × 24,000 = 55.3 cm3.