Question

Calculate volume of ch4 gas that contains 1.5 * 10 raise to 23 molecules

Answer 1

Hi there,

We know
PV=nRT
 
we know that P=1atm, R=0.0821 and T=273k
 to find n,
n=PV/RT

NOW,
n=1mol/Na X given no. of molecules
therefore, n=1/6.023x10^23 x 1.5x10^23
n=0.24moles
substituting it
n=1xV/8.021x273
V=525 L or mL
pls chk...with units
hope it helps
PLS MARK ITAS BRAINLIEST