Calculate volume of H2 gas kept at S.T.P if it contains as many H atoms as in 98 gm of H3PO4
Answers
Calculate volume of H2 gas kept at S.T.P if it contains as many H atoms as in 98 gm of H3PO4
Explanation:
Molar mass of the Phosphoric acid = 98 g/mole.
Mass of the Phosphoric acid = 98 g.
Therefore the number of molecules of the Phosphoric acid = 6.022 × 10²³ molecules.
Hence,
1 molecule of the Phosphoric acid have 3 atoms of Hydrogen.
∴ 6.022 × 10²³ molecules of Phosphoric acid have 6.022 × 10²³ × 3 atoms of Hydrogen = 1.81 × 10²⁴ atoms.
Hydrogen gas at S.T.P. also have the same number of atoms, 1.81 × 10²⁴ atoms.
Therefore Mass of the Hydrogen containing 1.81 × 10²⁴ atoms.
= Molar Mass × 1.81 × 10²⁴/Avogadro's number.
= 2 × 1.81 × 10²⁴/6.022 × 10²³
= 2 × 3
= 6 g.
1 mole of any gas at S.T.P. occupies the volume of the 22.4 liter.
Therefore 2 g of the Hydrogen at S.T.P. occupies the volume of the 22.4 liter.
Therefore 6 g of the Hydrogen at S.T.P. occupies the volume of the 22.4 × 6/2 liter.
= 22.4 × 3 = 67.2 liter.
Hence, the volume of the Hydrogen at S.T.P. is 67.2 liter.