Question

calculate volume of hydrogen gas obtained by by reacting 48 gram magnesium with 50 gram Hydrochloric acid at STP .

Plz provide clear solution..​

Answer 1

Answer:

Moles of magnesium:

50.0

⋅

g

24.31

⋅

g

⋅

m

o

l

−

1

=

2.06

m

o

l

Moles of hydrogen chloride gas:

75.0

⋅

g

36.2

⋅

g

⋅

m

o

l

−

1

=

2.07

m

o

l

Given equimolar amounts, clearly, the gas is in deficiency as the stoichiometric equation requires 2 equiv of gas per equiv of metal.

So, the

1

mole of gas evolves, (conveniently, as at

S

T

P

the molar volume is

22.4

d

m

3

).