Question

calculate volume of O2 produced from 54g of H2O according to following equation.?
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Answer 1

Answer:

33.6L

Explanation:

2H₂O = 2H₂ + O₂

No. of moles of H₂O = 54/18 = 3mol

∵ 2 moles of H₂O gives 1 mole of O₂

∴ 3 moles of H₂O will give 3/2 moles of H₂O

Again, 1 mole of gas occupies 22.4L

So, 3/2 moles of H₂O will occupy a volume = 3 X 22.4 /2 = 33.6L