calculate volume of SO3 is formed during the combustion of 1.6g of SO3
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Answer:
Please ask the question properly, Combustion of SO3 does not give SO3 itself.
The mole number of Sulphur atoms =1.6/32=0.05 mole
In STP volume of 1 mole gas is 22.4 L
In STP volume of 0.05 mole gas is 1.12 L
Explanation:
Assuming that here 1.6 g Sulphur combusted instead of SO3.
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