Calculate volume of water required to prepare 150ml og f 0.01m hcl from 0.1m hcl
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We have 10ml of 6.00 M HCl.
6.00M HCl means 6 moles of HCl are present in 1000 ml of its solution.
Thus , in 1ml of its solution 0.006 moles of HCl are present.
This implies , in 10ml 0.06 moles of HCl are present.
We want 0.5 M HCl which means we want 0.5 moles of it in 1000ml of its solution.
We have 0.06 moles of HCl .
Thus , volume of required to make it 0.5M is given by: moles of HCl / molarity of solution = 0.06/ 0.5 = 0.12 L
Thus , volume of solution should be 0.12L = 120 ml.
Volume of Water to be added = total final volume - initial volume = 120 - 10 = 110 ml
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