Question

calculate %w/w of Nacl in 1.2m Nacl aqueous solution (Nacl =58.5 g/mol​

Answer 1

Answer:

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Explanation:

here

3 Molar solution means  there are 3 moles of  NaCl salt in 1 Liter.  Molecular weight of NaCl = 58.44.    

Hence, there are 3×58.44 gms in 1 Litre of water.

Density =  

volume

mass

​  

 

Mass of 1 litre of solution = 1.25 gms/ml * 1000 ml = 1, 250 gms

V = volume of water added to make the solution

 175.32 gms + 1 gm /ml * V = 1, 250 gm

      ⟹V=1,074.68ml

So 1,074.68 ml or 1, 074.68 gms of water is mixed with 3 moles of Na Cl to make the 3 M solution.  

       

  Molality = mass of solute in number of moles / mass of solvent in kg

              =  

1.07468

3

​  

kg

              =2.7915 Molal

Answer 2

See if they have not mention the mass or volume of solution or solvent consider it as 1kg or liter

And they have given us the molality.

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