Chemistry, asked by Nishant722, 6 months ago

Calculate wave number for the longest wavelength transition in the Lyman
series of atomic hydrogen.

Answers

Answered by nis835985

0

Answer:

after nehngw qdvrg I can h gr

Answered by Anonymous

1

Answer:

n1=2

And n2=infinity

For balmar series...

Now apply formula

1/lembda=RZ^2(1/n1^2 -1/n2^2)

Where R= redburg constant

Explanation:

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