Question

calculate weight of ammonia formed by 5.6l of h2​

Answer 1

5.6 L of H₂ = $\frac{5.6}{22.4}$ = 0.25 moles

3 moles of H₂ reacts with 1 mole of N₂

Now, 0.25 moles of H₂ will react with:  0.083 moles of N₂

which will be: 0.083 x 22.4 = 1.8592 L of N₂ gas

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