Calculate weight of iron which will be converted into its oxide by action of 18 g of steam
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which oxide FeO ,Fe2O3,Fe3O4
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3Fe + 4H2O -> Fe3O4 + 4H2
3×56 gm of Fe react with 4×18 gm of H2O
3×56/4×18 gm of Fe react with 1 gm of H2O
3×56×18/4×18 gm of Fe react with 18 gm of H2O
wt of Fe= 42gm
3×56 gm of Fe react with 4×18 gm of H2O
3×56/4×18 gm of Fe react with 1 gm of H2O
3×56×18/4×18 gm of Fe react with 18 gm of H2O
wt of Fe= 42gm
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