Question

Calculate weight of phosphorus (P4) required which contain same number of phosphorus atoms as in a simple contain 98 gram of H3Po4, 68 gram of PH3, 568 gram of P4O10?​

Answer 1

answer

First, we find the number of moles of S8 found within the sample.

6.41 g S8 * (1 mol S8/256.48 g S8) = .0250 mol S8

Now that we know the desired number of molecules, we perform the same prices but in reverse for the P4

.0250 mol P4 * (123.88 g P4/1 mol P4) = 3.10 g P4

This would be enough, but the question asks for the number of atoms to be equivalent and not the molecules so the 3.10 g P4 must be multiplied by two to get 6.20 g P4