Question

calculate weight of sodium presents in 50g Na2So4​

Answer 1

Answer:

Explanation:

Sodium sulfate is

N

a

2

S

O

4

First, calculate the moles of sodium sulfate you have in a 14.2g sample.

Find the molar mass of sodium sulfate

molar mass = atomic mass in grams

2(23) + 32 + 4(16) = 142 grams per mole

Divide the mass of the sample by the molar mass to obtain moles

14.2

g

142

g

m

o

l

−

1

= 0.1 mol

Now, for every 1 mol of

N

a

2

S

O

4

you have 2 moles of

N

a

+

ions. Multiple the moles of

N

a

2

S

O

4

that you found just then by 2 to obtain the moles of sodium ions.

Use Avogadro's number (6.022 x

10

23

) to find the number of ions present. (Recall that Avogrado's number is the number of particles per mole of a substance).

6.022 x

10

23

x 0.2 mol = 1.2044 x

10

23

ions

Answer 2

Given:

50 grams of Na2SO4 .

To find:

Weight of sodium in that sample?

Calculation:

In 1 mole of Na2SO4 (142 grams) , there is 46 grams of Sodium (i.e. 2 moles).

So, in 50 grams of Na2SO4 , weight of Sodium:

$= \dfrac{46}{142} \times 50$

$= 16.19 \: grams$

So, weight of Na (Sodium) present in that sample is 16.19 grams.