Question

Calculate what volume of oxygen will be liberated by hitting 1.225 gram of potassium chloride
​

Answer 1

Explanation:

2KClO

3

⟶

heat

2KCl+3O

2

2×122.5g of KClO

3

gives =

2×122.5

3×22.4

×12.25=3.36L of O

2

of STP.

Answer 2

Answer:

2KClO

3

⟶

heat

2KCl+3O

2

2×122.5g of KClO

3

gives =

2×122.5

3×22.4

×12.25=3.36L of O

2

of STP.