Question

Calculate work done during isothermal
reversible process when 5 mol ideal gas is
expanded so that its volume is doubled at 400 k? PLEASE ANSWER WITH CORRECT EXPLAINATION
​

Answer 1

The work done during isothermal  reversible process when 5 mol ideal gas is  expanded so that its volume is doubled at 400 K is 11525.6 Joules.

Explanation:

The expression used for work done in reversible isothermal expansion will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = ?

n = number of moles of gas  = 5 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 400 K

$V_1$ = initial volume of gas  = $V$

$V_2$ = final volume of gas  = $2V$

Now put all the given values in the above formula, we get:

$w=5mole\times 8.314J/moleK\times 400K\times \ln (\frac{2V}{V})$

$w=11525.6J$

The work done during isothermal  reversible process is 11525.6 Joules

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Answer 2

Explanation:

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