calculate work done in compressing 10xm a spring of force constant 1000N/m (by external agent?
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Step-by-step explanation:
Work done by spring=work applied to spring
Therefore work= 1/2*k*x^2 = 1/2*1000*10x*10x=50,000*x^2J= 50*x^2KJ
The work done depends on the spring constant K as well as the distance moved x. As we can see through the formula the work done is directly proportional to the spring constant and distance moved. Hence whatever work is done on the spring is stored as a potential energy form in the system and can be converted into kinetic energy whenever required.
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