Calculate work done required to stop an object of 120 kg moving with a velocity of 9 km/h.
Answers
Explanation:
Answer:
Mass of the car (m) = 1500 kg
Velocity (v) = 60 km/hr
v = 60 x 5/18
v = 16.67 m/s
The car is in motion, so its energy is,
Kinetic Energy (K.E) = 1 /2 mv2
\(\begin{array}{l}K.E = \frac{1}{2}\times 1500 \times ( 16.67)^{2}\end{array} \)
K.E = 1/ 2 × (1500) × 277.88 J
K.E = 208416.7 J
The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208416.7 – 0
= 208416.7 J
Hence, the work required to stop the car is 208416.7
Answer:
Mass of the car (m) = 1500 kg
Velocity (v) = 60 km/hr
v = 60 x 5/18
v = 16.67 m/s
The car is in motion, so its energy is,
Kinetic Energy (K.E) = 1/2 mv2
\\begin{array}{I}K.E=\frac{1}{2}\times 1500 \times (16.67)^{2}\end{array} \)
K.E = 1/2 × (1500) × 277.88 J
K.E = 208416.7 J
The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208416.7 -0The kinetic energy of the car, when it comes to rest = 0 J
Work done on object = change in kinetic energy
= 208416.7 - 0 =
= 208416.7 J
Hence, the work required to stop the car is 208416.7