Calculate work required to be done to stop a car of 1500 kg moving at a velocity of 60 km per hour
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Mass of car, m = 1500 kg
velocity, v = 60 km/h = 60 \times \frac{5}{18}=16.67\ ms^{-1}
Kinetic energy possessed by the car = \frac{1}{2} mv²
⇒ KE = \frac{1}{2} \times 1500 \times 16.67^2=208416.7\ J=208.4\ kJ
To stop the car, we have to make the KE of car 0. So the work need to be done is 204.4 kJ.
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ANSWER :
VELOCITY : Velocity is the speed of an object moving in definite direction.
S.I Unit : m/s
Average velocity = initial velocity + final velocity / 2
WORK DONE = Force × Distance moved
→ Mass = 1500 kg
v = 60 km/h
= 60 × 1000 / 60 × 60 m/s
= 50/3 m/sec
WORK DONE TO STOP A CAR = ENERGY REQUIRED = KINETIC ENERGY
∴ KINETIC ENERGY = 1/2 mv²
= 1/2 × 1500 × ( 50/3 ) ²
= 208333.3 J
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