Math, asked by tanishkasahu83v, 3 days ago

calculate x in the following figure.

please solve the full question.
and explain in the answer​

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Answers

Answered by Yuseong
58

Answer:

16 cm

Step-by-step explanation:

As ∆ABC is a right angled triangle, so by using Pythagoras property,

  • BC = Base
  • AB = Hypotenuse = 55 cm
  • AC = Perpendicular = 44 cm

= +

→ AB² = BC² + AC²

→ AB² ― AC² = BC²

→ (55 cm)² ― (44 cm)² = BC²

→ 3025 cm² ― 1936 cm² = BC²

→ 1089 cm² = BC²

→ √(1089 cm²) = BC

33 cm = BC⠀⠀⠀⠀⠀⠀⠀⠀ ( 1 )

Now, In ∆BCD :

  • BC = Perpendicular = 33 cm (Found above)
  • BD = Base = 56 cm
  • CD = Hypotenuse

By using Pythagoras property,

H² = B² + P²

→ CD² = BD² + BC²

→ CD² = (56 cm)² + (33 cm)²

→ CD² = 3136 cm² + 1089 cm²

→ 4225 cm² = CD²

→ √(4225 cm²) = CD

65 cm = CD⠀⠀⠀⠀⠀⠀⠀⠀… ( 2 )

Now, in ∆CDE :

  • CD = Hypotenuse = 65 cm (Found above)
  • DE = Base = 63 cm
  • CE = Perpendicular = x

H² = B² + P²

→ CD² = DE² + CE²

→ CD² ― DE² = CE²

→ (65 cm)² ― (63 cm)² = CE²

→ 4225 cm² ― 3969 cm² = CE²

→ 256 cm² = CE²

→ √(256 cm²) = CE

16 cm = CE

Therefore, the value of x is 16 cm.  \;

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Answered by as8214085
31

GIVEN :-

a figure

to calculate :-

value of x = ?

SOLUTION :-

In ∆ ABC by pythagoras theorem

BC = √(AB) ^ 2 - ( Ac) ^ 2)

BC = √ (55) ^ 2 - (44) ^ 2

BC = √ 3025 - 1936

BC = √1089 = 33 cm

IN ∆ BCE by pythagoras theorem:-

EC = √(BE) ^ 2 + (BC) ^ 2)

EC = √(56) ^ 2 + (33) ^ 2)

EC = √ 3136 + 1089

EC = √ 4225 = 65 cm

IN ∆ EDC :-

(CD) = √ (CE) ^ 2 - (ED) ^ 2)

x = √(65) ^ 2 - (63) ^ 2)

x = √ 4225 - 3969

x = √ 256 = 16 cm

Hence the value of x is 16cm is the

answer.

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