Question

calculate yhe amount of chargethe would flow in one hourthrough the element of an electric iron drawing a current of 0.4amps.​

Answer 1

Using the relation,

Q = I*t

I = 0.4 A

t = 1 hour

= 1*60*60 seconds

= 3600 seconds

Q = 3600 s * 0.4 A

= 1440 C