Question

calculate% yield of the reaction if 1 kg khco3 produced 110gm of Co2 upon strong heating​

Answer 1

Answer: Percentage yield for the reaction is 50%.

Explanation:-

$2KHCO_3\rightarrow K_2CO_3+CO_2+H_2O$

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles

According to stochiometry:

2 moles of $KHCO_3$ produce 1 mole of $CO_2$

$2mol\times 100g/mol=200g$ of $KHCO_3$ produce $1mol\times 44g/mol=44g$ of $CO_2$

Thus 1000 g of $KHCO_3$ should produce $\frac{44g}{200g}\times 1000g=220g$ of $CO_2$

Thus theoretical yield of $CO_2$ is 220 g.

But Experimental yield is 110 g.

${\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%$

${\text {percentage yield}}=\frac{110g}{220g}\times 100\%=50\%$

Hence percentage yield for the reaction is 50%.