Calculate Young’s modulus of the material of a wire of length 3.5m and diameter 0.3mm, when the elongation is 2mm, under a tension of 0.75kg
Answers
Answer:
What is the force needed to stretch a spring, with a k = 13 N/m a total of 0.16 m?
Data Equation Math Answer
k = 13 N/m
x = 0.16 m
F = kx F = 13 (0.16) 2.08 N
4. A spring has a k = 28 hangs at 85.4 cm above the tabletop. How high above the table will the bottom of the
spring be if 6.5 N are applied to the spring?
Data Equation Math Answer
k = 28
hi = 0.854 m
F = 6.5 N
hf = |hi - x|
x = F ÷ k
x = 6.5 ÷ 28 = 0.232
hf = 0.854 – 0.232
0.622 m
5. The bottom of a spring with a k = 24.5 N/m is 0.125 m above a tabletop when 12.5 N are attached. If the weight
is removed, how far above the tabletop will the spring hang?
Data Equation Math Answer
k = 24.5 N/m
hf = 0.125 m
F = 12.5 N
hi = hf + x
x = F ÷ k
x = 12.5 ÷ 24.5 = 0.510
hf = 0.125 + 0.510
0.635 m
6. A 250 g mass is hung from a spring that stretches from 93.4 cm to 62.2 cm. What is the k for the spring?
Data Equation Math Answer
m = 0.250 kg
hi = 0.934 m
hf = 0.622 m
k = F÷ x
x = |hf - hi|
F = mg
x = 0.622 – 0.934 = 0.312
F = 0.250 (9.81) = 2.45 N
k = 2.45/0.312
7.86 N/m
7. A spring with a k = 15.3 N/m hangs 3.5 cm above a tabletop when a 400 g mass is hung from it. If the mass
were removed, how far above the tabletop will be the bottom of the spring?
Data Equation Math Answer
k = 15.3 N/m
hf = 0.035 m
m = 0.400 kg
hi = hf + x
x = F ÷ k
F = mg
F = 0.4 (9.81) = 3.92 N
x = 3.92/15.3 = 0.256 m
hi = 0.035 + 0.256
0.291 m
Or 29.1 cm
Explanation:
What is the force needed to stretch a spring, with a k = 13 N/m a total of 0.16 m?
Data Equation Math Answer
k = 13 N/m
x = 0.16 m
F = kx F = 13 (0.16) 2.08 N
4. A spring has a k = 28 hangs at 85.4 cm above the tabletop. How high above the table will the bottom of the
spring be if 6.5 N are applied to the spring?
Data Equation Math Answer
k = 28
hi = 0.854 m
F = 6.5 N
hf = |hi - x|
x = F ÷ k
x = 6.5 ÷ 28 = 0.232
hf = 0.854 – 0.232
0.622 m
5. The bottom of a spring with a k = 24.5 N/m is 0.125 m above a tabletop when 12.5 N are attached. If the weight
is removed, how far above the tabletop will the spring hang?
Data Equation Math Answer
k = 24.5 N/m
hf = 0.125 m
F = 12.5 N
hi = hf + x
x = F ÷ k
x = 12.5 ÷ 24.5 = 0.510
hf = 0.125 + 0.510
0.635 m
6. A 250 g mass is hung from a spring that stretches from 93.4 cm to 62.2 cm. What is the k for the spring?
Data Equation Math Answer
m = 0.250 kg
hi = 0.934 m
hf = 0.622 m
k = F÷ x
x = |hf - hi|
F = mg
x = 0.622 – 0.934 = 0.312
F = 0.250 (9.81) = 2.45 N
k = 2.45/0.312
7.86 N/m
7. A spring with a k = 15.3 N/m hangs 3.5 cm above a tabletop when a 400 g mass is hung from it. If the mass
were removed, how far above the tabletop will be the bottom of the spring?
Data Equation Math Answer
k = 15.3 N/m
hf = 0.035 m
m = 0.400 kg
hi = hf + x
x = F ÷ k
F = mg
F = 0.4 (9.81) = 3.92 N
x = 3.92/15.3 = 0.256 m
hi = 0.035 + 0.256
0.291 m
Or 29.1 cm