Question

calculate z effective of copper for 4s​

Answer 1

Answer:

Cu: 1s2 2s2 2p6 3s2 3p6 3d10 4s1

For the 4s electron:

29 - [18(0.85) + 10(1.0)] = 3.7

For the 3d electron:

29 - [9(0.35) + 18(1.0)] = 7.85

You can conclude that the 4s electron experiences a lower effective nuclear charge and is therefore more likely to be lost than the 3d electron, should the copper atom become ionized.