Calculate Zeff for 3s electron in vanadium(23). correct answer will be marked as brainliest
Answers
1s2 2s2 2p6 3s2 3p6 4s2 3d3
for outermost e- in s screening constant (sigma)=0
now, METHOD TO CALCULATE Z EFF↓↓
→ Each n 'e' contribute =0.35
→ each (n-1) 'e' contribute = 0.85
→ each (n-2), (n-3)....contribute =1
hete, n = outermost shell number
now,
calculate Zeff for Vanadium,
=>( 1×0.35) + (11×0.85) + (10×1)
=> 0.35 + 9.35 + 10
=> 19.70
Zeff =( Z - sigma)
= (23-14.70)
= 8.30
(^_-)
Answer:
Zeff for 3s electron in vanadium(23) is 13.5
Explanation:
Given,
Vanadium whose atomic number (Z) = 23
To find,
The Zeff of 3s electron present in Vanadium
Calculation,
We know that,
Zeff = Z - σ...(1)
Where,
Zeff = effective nuclear charge,
Z = Atomic number,
And σ = screening constant
Now we try to calculate the screening constant for 3s electron in vanadium,
The electronic configuration of Vanadium(23) is:
1s² 2s² 2p⁶ 3s² 3p⁶ 3d³ 4s²
Now σ is defined as:
σ = 0.35 (no. of electrons in nth shell) + 0.85 (number of electrons in (n - 1)th shell) + 1 (number of electrons in (n - 2)th shell)
⇒ σ = 0.35 (no. of electrons in 3s shell) + 0.85 (number of electrons in (2s + 2p) shell) + 1 (number of electrons in 1s shell)
⇒ σ = 0.35 × 2 + 0.85 × 8 + 1 × 2
⇒ σ = 9.5
Hence, from equation (1)
Zeff = 23 - 9.5
⇒ Zeff = 13.5
Therefore, Zeff for 3s electron in vanadium(23) is 13.5
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