Question

Calculated De-broglie wavelength ofstone of mass 50 gm and velocity 50 m/sec and electron of potential 120V​

Answer 1

Answer:

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According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of object=200 g= 0.2 kg and v= velocity=5m/h=5/3600 m/s

upon substitution we get:

λ=

0.2×5

6.626×10

−34

×3600

λ=2.385×10

−30

m

Answer 2

Answer:

According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of object=200 g= 0.2 kg and v= velocity=5m/h=5/3600 m/s

upon substitution we get:

λ=

0.2×5

6.626×10

−34

×3600

λ=2.385×10

−30

m

Explanation:

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