Question

Calculated mole fraction of solute in aqueous 4m solution assuming the density of the solution as0. 1g/ml

Answer 1

Answer:

Explanation:

Molality is basically number of moles solute present in the 1kg of solvent.

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water.

Molefraction is the ratio of the number of moles of solute and total number of moles in solution.

Molecular mass of water (H2O) = 18

Given mass of water = 1000 (1 kg)

Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.

Molefraction of solute = (moles of solute) / (total number of moles)

Therefore 1/(55.5+1) = 0.017.

Molefraction of solute in 1 m aqueous solution is 0.017.