Question

Calculated the half life of the radioisotope if it's Mass decreased from 24g to 6g over a period of 6 day's​

Answer 1

Explanation:

N / No = (½) ^ n

6 / 24 = (½) ^ n

1/4 = (½)^ n

n = 2

then

T = n x t½

6 = 2 x t½

t½ = 3 days