Question

Calculated the length of a chord which is at a distance 12 cm from the centre of a circle of radius 13 cm.​

Answer 1

Answer:

10 cm.

Step-by-step explanation:

According to Pythagoras Theorem,

$h {}^{2} = p {}^{2} + b^{2}$

or, 13^2 = 12^2 + B^2

or, 169 = 144 + B^2

or, B^2 = 169 - 144

or, B^2 = 25

or, B = 5

Since the perpendicular drawn from the centre of the circle divides the chord into two equal parts, the length of the chord will be 10 cm.