Calculatethe number of atoms of hydrogen present in 5.6g of urea
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Answer: Urea = NH2CONH2. M.wt = 60. 5.6 g urea = 5.6/60 = 0.093 moles. 1 mole of urea contains 4N atoms of H. 0.093 moles contains 0.093 x 4N .
Explanation:
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Answer:
1g = 6.26 × 10^26
so 5g = 5 × 6.26 × 10^26
==31.3 × 10^ 26
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