Question

Calculating Average Force
We can calculate the average acceleration of the Curiosity rover during its landing on Mars using the initial velocity, vi , the final velocity, vf , and the time it took to stop:

a=vf−vit

According to Newton’s second law, the average force required to slow the Curiosity rover to a stop, F , is equal to the mass of the rover, m , multiplied by its average acceleration, a :

F=ma

Use these equations to calculate the average force required to stop the Curiosity rover if the initial velocity is 5,300 m/s, the final velocity is 0 m/s, the time required to stop is 7 minutes, and the mass of the rover is 533 kg. (Be sure to convert the time, 7 minutes, to seconds!)

Answer 1

Answer:

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Answer 2

The force required to stop Curiosity Rover is 6725.95 newtons.

Let a be the  average acceleration of the Curiosity rover during its landing on Mars using the initial velocity, Vi , the final velocity, Vf , and the time t it took to stop.

1. Here t = 7*60 seconds

1. Therefore a = (Vf-Vi)/t

                       =(0-5300)/7*60

                       =-12.62 m/$s^{2}$ ( approx)  

3. Here the negative sign represents the deceleration of the Curiosity rover.

4. Now the force required to stop the Curiosity rover = m*a

                                                                                        = 533*12.62

                                                                                        = 6725.95 N (approx)

    Here m= mass of Curiosity rover .