Question

calculating
pannung its all surfaces with coaltar at 2.25 per square dcm.
Height of a hollow right circular cylinder, open at both ends, is 2.8 metre. Iflength of inner
diametre of the cylinder is 4.6 dcm and the cylinder is made up of 84.48 cubic dem of iron,
sus calculate the length of outer diameter of the cylinder​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

GIVEN: A hollow Cylindrical shell.. Outer radius R= 7 cm, internal radius r = 6 cm, & height h = 22 cm

TO FIND: TSA ie( external Surface area + internal surface area + area of concentric circular region at both the open ends..

External surface area = 2 pi R h = 2*pi * 7 * 22 = 308pi ………….(1)

Internal surface area = 2 pi r h = 2* pi * 6 * 22 = 264pi ………….(2)

Now, area of concentric circular region at one end = pi R² - pi r² = pi ( 7² - 6²) = pi (7+6)(7–6) = pi* 13 *1 = 13pi

So, at both the ends,area= 13pi*2 = 26pi …..(3)

So, total surface area of the cylindrical shell=

308pi + 264pi + 26pi

= 598pi cm² …………Ans

Step-by-step explanation:

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