calculating the power of a pump lifting 200 kg of water and storing it in a water tank of height 10 meter in 25 second
Answers
Answer:
Given :-
Mass of the water lifted = 200 kg
Height carried by the pump = 6 m
Time taken to carry = 10 sec
To Find :-
The power of the pump.
Analysis :-
Here we are given with the mass, height and time taken to carry the water.
Firstly find the work done by substituting the given values in it's respective formula.
Then find the power done by substituting the values such that power is equal to work done divided by the time taken.
Solution :-
We know that,
m = Mass
h = Height
w = Work done
t = Time
g = Gravity
p = Power
Using the formula,
Given that,
Mass (m) = 200 kg
Gravity (g) = 10 m/s
Height (h) = 6 m
Substituting their values,
⇒ w = mgh
⇒ w = 200 × 10 × 6
⇒ w = 2000 × 6
⇒ w = 12000 J = 1.2 × 10⁴ J
Using the formula,
Given that,
Work done (w) = 1.2 × 10⁴ J
Time (t) = 10 sec
Substituting their values,
⇒ p = 1.2 × 10⁴/10
⇒ p = 1200 W
Therefore, the power of the pump is 1200 W.
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the inside and outsidGiven :-
Mass of the water lifted = 200 kg
Height carried by the pump = 6 m
Time taken to carry = 10 sec
To Find :-
The power of the pump.
Analysis :-
Here we are given with the mass, height and time taken to carry the water.
Firstly find the work done by substituting the given values in it's respective formula.
Then find the power done by substituting the values such that power is equal to work done divided by the time taken.
Solution :-
We know that,
m = Mass
h = Height
w = Work done
t = Time
g = Gravity
p = Power
Using the formula,
Given that,
Mass (m) = 200 kg
Gravity (g) = 10 m/s
Height (h) = 6 m
Substituting their values,
⇒ w = mgh
⇒ w = 200 × 10 × 6
⇒ w = 2000 × 6
⇒ w = 12000 J = 1.2 × 10⁴ J
Using the formula,
Given that,
Work done (w) = 1.2 × 10⁴ J
Time (t) = 10 sec
Substituting their values,
⇒ p = 1.2 × 10⁴/10
⇒ p = 1200 W
Therefore, the power of the pump is 1200 W.