Question

calculating the resulting source if a steel ball of radius 6cm which immersed in water. assume the density of steel is 7900 per metre cube​

Answer 1

Answer:

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Answer 2

Given,

Radius of steel = 0.06m

Volume = 4/3pier^3

V= 4/3×0.06^3

V=9.05×10^-4

Density of water= 10^-3

Buoyant force = p×g×v

= 8.87N

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