calculating the resulting source if a steel ball of radius 6 CM which immersed in water assume the density of steel is 7900 per metre cube
Answers
Answered by
3
Answer:
solved
Explanation:
volume = 4πx0.06³/3m³
mass = 4πx72x10∧-6 x 7.9x10³ kg
weight = 4πx72x10∧-6 x 79x10³N = 71.5N
Answered by
1
Answer:
radius of steel ball =6 cm =0.06m
volume of steel ball=43r^3
v = 430.063
v = 9.0510 ( -4) m^3
Density of water = 1000 kg m^-3
Gravity = 9.8 ms ^-2
from Archimedes principal formula
Fb = g V
( 1000kg ^ -3 ) ( 9.8 ms ^-2) ( 9.0510 - 4 m ^3)
Fb = 8.87 N Answer_
Similar questions