Question

Calculating using Newton’s 2nd Law of Motion

Answer 1

Newton's second law of motion:

Newton's second law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force. So, mathematically,

F = ma

Where,

• F denotes force
• m denotes mass of the object
• a denotes acceleration produced by the effect of force.

$\:$

Answer-1:

• Mass of the golf ball = 0.2 kg
• Acceleration = 20 m/s²
• Force acting on the ball = ?

F = ma

F = 0.2×20

$\boxed {\bf {\red {F = 4\ N}}}$

$\:$

Answer-2:

• Mass of shopping cart = 18 kg
• Acceleration of the cart = 3 m/s²
• Force acting on the cart = ?

F = ma

F = 18×3

$\boxed {\bf {\pink {F = 54\ N}}}$

$\:$

Answer-3:

• Mass of the cup = 0.025 kg
• Acceleration = 5 m/s²
• Force exerted by the wind on the paper cup = ?

F = ma

F = 0.025×5

$\boxed {\bf {\blue {F = 0.125\ N}}}$

$\:$

Answer-4:

• Mass of the girl = 50 kg
• Acceleration = 4 m/s²
• Force applied by you = ?

F = ma

F = 50×4

$\boxed {\bf {\orange {F = 200\ N}}}$

$\:$

Answer-5:

• Mass of the friend = 70 kg
• Acceleration = 4 m/s²
• Force exerted = ?

F = ma

F = 70×4

$\boxed {\bf {\purple {F = 280\ N}}}$

$\:$

Answer-6:

• Mass of the hammer = 9 kg
• Acceleration due to gravity = 9.8 m/s²
• Force exerted by the earth on the hammer.

F = ma

F = 9×9.8

$\boxed {\bf {\green {F = 88.2\ N}}}$

Answer 2

Newton's second law of motion:

Newton's second law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force. So, mathematically,

F = ma

Where,

F denotes forcem denotes mass of the objecta denotes acceleration produced by the effect of force.

\:

Answer-1:Mass of the golf ball = 0.2 kgAcceleration = 20 m/s²Force acting on the ball = ?

F = ma

F = 0.2×20

\boxed {\bf {\red {F = 4\ N}}}F=4 N

\:

Answer-2:Mass of shopping cart = 18 kgAcceleration of the cart = 3 m/s²Force acting on the cart = ?

F = ma

F = 18×3

\boxed {\bf {\pink {F = 54\ N}}}F=54 N

\:

Answer-3:Mass of the cup = 0.025 kgAcceleration = 5 m/s²Force exerted by the wind on the paper cup = ?

F = ma

F = 0.025×5

\boxed {\bf {\blue {F = 0.125\ N}}}F=0.125 N

\:

Answer-4:Mass of the girl = 50 kgAcceleration = 4 m/s²Force applied by you = ?

F = ma

F = 50×4

\boxed {\bf {\orange {F = 200\ N}}}F=200 N

\:

Answer-5:Mass of the friend = 70 kgAcceleration = 4 m/s²Force exerted = ?

F = ma

F = 70×4

\boxed {\bf {\purple {F = 280\ N}}}F=280 N

\:

Answer-6:Mass of the hammer = 9 kgAcceleration due to gravity = 9.8 m/s²Force exerted by the earth on the hammer.

F = ma

F = 9×9.8

\boxed {\bf {\green {F = 88.2\ N}}}F=88.2 N

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