Calculation based on molar volume
Calculate the volume occupied by:
23
1)3.011 - 10 of ammonia gas molecules.
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Answer:
3.011×10
23
no. of nitrogen atom at mass of nitrogen =14g
1 mole of nitrogen contains 6.022×10
23
atoms
14g will contains 6.022×10
23
atoms
how,
6.022×10
23
14
g contains 1 atom
∴(
6.022×10
23
14
)×3.011×10
23
=
2
14
=7g of N.
Explanation:
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