Question

calculation of oxidation state of copper in cupric oxide​

Answer 1

Answer:

This is too broad a question, you can't memorize its oxidation states, per se, but you can rationalize what it is by memorizing the rules for common anions it usually bonds with!

Explanation:

For instance,

C

u

S

O

4

— copper (II) sulfate

x

+

(

+

6

)

+

(

−

8

)

=

0

We know sulfate's charge is 2-, and we also memorize that an oxide anion has an oxidation state of 2-, unless its a peroxide in which case its charge is 1-, but that's another question!

So, solving this 8th grade algebra problem, we get:

x

−

2

=

0

x

=

2

Thus, in this particular compound, copper's oxidation state is 2+!

Answer 2

Explanation:

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