calculation of oxidation state of copper in cupric oxide
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Answered by
0
Answer:
This is too broad a question, you can't memorize its oxidation states, per se, but you can rationalize what it is by memorizing the rules for common anions it usually bonds with!
Explanation:
For instance,
C
u
S
O
4
— copper (II) sulfate
x
+
(
+
6
)
+
(
−
8
)
=
0
We know sulfate's charge is 2-, and we also memorize that an oxide anion has an oxidation state of 2-, unless its a peroxide in which case its charge is 1-, but that's another question!
So, solving this 8th grade algebra problem, we get:
x
−
2
=
0
x
=
2
Thus, in this particular compound, copper's oxidation state is 2+!
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Explanation:
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