calculation of oxidation state of copper in cupric oxide
Answers
Answered by
1
Step-by-step explanation:
Cupric oxide=Cu2O.
O=-2.
2×Cu+1×(-2)=0
2Cu-2=0
2Cu=2
Cu=2/2=1.
oxidation state of copper in cupric oxide is +1..
Answered by
1
Answer:
I hope it helpful.....
Attachments:
Similar questions
Physics,
3 months ago
Hindi,
3 months ago
Chemistry,
7 months ago
Social Sciences,
11 months ago
Social Sciences,
11 months ago
Social Sciences,
11 months ago