Question

calculation percentage composition of nitrogen and carbon in urea nh2conh2​

Answer 1

Answer:

The percentage of Nitrogen in urea is 46.7%.

Explanation:

The chemical formula of urea is NH2-CO-NH2.

Here the molar mass of:

N=14u

C=12u

O=16u

H=1u

Molar mass of NH2-CO-NH2=(2X14)+12+16+(4X1)=60

Mass % of N=(Mass of N in urea/Total mass)X100

=(28/60)X100

=46.7%

Answer 2

Answer:

Percentage of Carbon: 20%

Percentage of Nitrogen: 46.67%

Explanation:

Firstly, we calculate the molecular mass of Urea, $NH_{2}CONH_{2}$.

= (Atomic masses: Nitrogen = 14; Hydrogen = 1; Carbon = 12 Oxygen = 16)

= 14 + 2(1) + 12 + 16 + 14 + 2(1)

= 60.

We have found the Molecular Mass of Urea

Now, we need, percentage of (i) Carbon, and (ii) Nitrogen.

(i) Carbon = $\frac{12}{60}$ × 100 = 20%

(ii) Nitrogen = $\frac{28}{60}$ × 100 = 46.67%

The Percentage of Carbon: 20%,

The Percentage of Nitrogen: 46.67%

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